Calculate the t value of the set of data using avg=98.59, s=0.097,n=5, Df=4
t=X-u/s/sqrt 5 = 4.14.
the critical value for t at 0.05/2,4 (two tailed t test ) is 2.78
since the calculated value of 4.14 exceeds the critical value of t we reject the null hypothesis and conclude that the average is different than the theoretical value at the95% CI