Math for College Readiness (yes or no question)

Question

Does the graph of the straight line with slope of 5 and y- intercept of -1 pass through the point (1,-2)?

Answer 1

The slope-intercept form of the equation of a line is: y = mx+b

where: m is the slope

b is the y-intercept (the point on the line where x=0)

slope, m=5

y-intercept = -1

equation: y = 5x - 1

The point (1,-2) is on that line if: (-2) = 5(1) - 1

Is the point on that line?

Answer 2

since you are given the slope and the y-intercept directly i would plug those into the equation

y = mx + b

y = 5x - 1

then you want to plug in the given point of (1, -2) and see if it holds for this expression

-2 = 5(1) - 1

-2 = 5 - 1

-2 = 4

since those are not equal that means that the point is not on the line