The equation y = 3/4X + 1 represents a given line.. Write the equation for the line that passes through (6,6) and is perpendicular to the given line

Answer 1

Equation of line is y = mx + b, where m is the slope and b is the y-intercept

For line y = (3/4)x + 1, 3/4 is the slope

The slope of the line perpendicular to that is the negative reciprocal, or -4/3

Since (6,6) is a point on the line, we then substitute x = 6, y = 6 and m = -4/3 into the y = mx + b equation to determine b:

6 = -4/3(6) + b

6 = - 8 + b

14 = b

so equation of the perpendicular line is y = (-4/3)x + 14

Answer 2

perpendicular line has a negative inverse slope = -4/3

(y-6)/(x-6) = -4/3

cross multiply

3y-18 = -4x +24

4x +3y = 42 is the perpendicular line through the point (6,6)