what is the equation of the line with a slope of 3 and passing through the point (1,-3)

Answer 1

Use the slope-intercept form to write this equation.

y=mx+b

m= slope. Slope is given. m=3

b= y-intercept

Substitute m=3

y=3x+b

Substitute x=1 and y=-3 (given by the point (1,-3) in the question)

-3=3(1)+b Solve for b.

-3=3 + b Subtract 3 on both sides to isolate the variable, b.

-3 -3 =b

-6 = b

Now, substitute m=3 and b=-6 to the equation

y=mx+b

y=3x - 6

Final Answer: y= 3x - 6

Answer 2

Y = 3x -6

Slope is 3 so in y= mx +b m is 3.

(1,-3) would be x and y point respectively

-3 = 3(1) +b

B = -6