
Yefim S. answered 12/13/21
Math Tutor with Experience
D(x) = s(x); (x - 3)2 = x2 + x - 5; x2 - 6x + 9 = x2 + x - 5; 7x = 14; x = 2 units for equilibrium price.>Price D(2) = s(2) = 1.
CS = ∫02[(x - 3)2 - 1]dx = [(x - 3)3/3 - x]02 = (- 1/3 - 2) + 9 = 20/3
PS = ∫02(1 - x2 - x + 5)dx = (6x - x3/3 - x2/2)02 = 12 - 8/3 - 2 = 22/3