Bradford T. answered 12/12/21
Tutor
4.9
(29)
Retired Engineer / Upper level math instructor
A = ∫24 x2-6x+9 dx
= x3/3-3x2+9x |24 = (64/3)-48+36-(8/3)+12-18 = (56/3)-18 = (56-54)/3 = 2/3
Answer #1
Bradford T. answered 12/12/21
Retired Engineer / Upper level math instructor
A = ∫24 x2-6x+9 dx
= x3/3-3x2+9x |24 = (64/3)-48+36-(8/3)+12-18 = (56/3)-18 = (56-54)/3 = 2/3
Answer #1
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