V = int(dV/dt)dt) you are given the rate at different times. I believe you are supposed to use the right side rectangle approximation:
After 48 hours, the V = (6.9 gal/6 hours)(t-48) or use t after 48
V = 6hr( 6.5 + 12.7 + .... + 486.9 gal/hr)
since the last interval is 6 x 486.9 we're already over 2500. so the limit has to happen in the first 48 hours
I would just do 6 hrs * 6.5 gal/hr + 6*12.7 + ... until I hit > 2500 gal
I'd estimate the time as the midpoint in the t interval to the left of the last side I used. You could also linearly interpolate to the last value, but it's unnecessary with the MC format. Basically, add up to 30 hrs. If you hit, answer is 27 and, 33.5 otherwise.