math question in need of help

Question

Solve the triangle using the Law of Sines. (Assume b = 4,

 ∠A = 50°,

 and ∠C = 100°.

 Round the lengths to two decimal places.)

a	=
c	=
∠B	=	°

Answer 1

sinB/b = sinA/a = sinC/c

B= 180-A-C

B = 180-50-100 = 30

sin30/4 = sin50/a = sin100/c

sin30=1/2

1/8 = sin50/a

a = 8sin50

= 8(.766)=6.128

=6.13

1/8 = sin100/c

c = 8sin100

=8(.9848)= 7.8784

= 7.88

C>A>B

100>50>30

so

c>a>b

7.88>6.13>4