
Yefim S. answered 12/05/21
Math Tutor with Experience
A. xC = (m1x1 + m2x2)/(m1 + m2) = (5·(-9.7) + 12·10.9)/(5 + 12) = 3.56m
B. r1 = 3.56 - (- 9.70) = 13.26m; r2 = 10.9 - 3.56 = 7.34 m
C> I = m1r12 + m2r22 = 5·13.262 + 12·7.342 = 1525.65 kgm2.
Hannah E.
asked 12/05/21If m1 = 5.00 kg is located at x1 = -9.70 m and m2 = 12.0 kg is located at x2 = 10.9 m, then
B. How far is each mass from the center of mass?
r1 = m
r2 = m
C. What is the system's moment of inertia about an axis through the center of mass and perpendicular to the x-axis?
I = kg m2
Yefim S. answered 12/05/21
Math Tutor with Experience
A. xC = (m1x1 + m2x2)/(m1 + m2) = (5·(-9.7) + 12·10.9)/(5 + 12) = 3.56m
B. r1 = 3.56 - (- 9.70) = 13.26m; r2 = 10.9 - 3.56 = 7.34 m
C> I = m1r12 + m2r22 = 5·13.262 + 12·7.342 = 1525.65 kgm2.
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