
James H.
asked 12/04/21Newton's method question
Use Newton's method to approximate a root of the equation x3+x+2=0 as follows.
Let x1= − 1 be the initial approximation.
The second approximation x2 is
third approximation x3 is
1 Expert Answer

Yefim S. answered 12/04/21
Math Tutor with Experience
f(x) = x3 + x+ 2; f'(x) = 3x2 + 1
xn + 1 = xn - f(xn)/f'(xn), n ≥ 1
x1 = - 1
x2 = -1
x3= -1.
This is because x = -1 is exact zero of the equation
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Doug C.
Are you sure you have the equation posted correctly? "-1" is the actual root of the equation, no need for Newton's method.12/04/21