Michael J. answered 03/13/15
Tutor
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Mastery of Limits, Derivatives, and Integration Techniques
Your solution is
B) (x + 2)2 - 1
The function (x + 2)2 acts like the graph x2. x2 always starts on the second quadrant and decreases in y-value from its starting point as x increases. If you plug in x = -2, f(-2) = -1.
f(-2) = (-2 + 2)2 - 1
f(-2) = 0 - 1
f(-2) = -1
(-2, 1) is point where the graph starts to increase as the x-values increase. Also, this point is in the second quadrant. In addition, the function x2 is a reflection over the positive y-axis which is between the first and second quadrants.