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simplify f(x)=(x^2-x)/(x-1)

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While (x^2-x)/(x-1) does simplify to x, it is not true that g(x) and f(g) are not equivalent. Because f(x)=x except at x=1 and is undefined at x=1. Meanwhile g(1)=1.


I think that means yes and no:  f=g for every value except x=1