Inactive Tutor answered 11/26/21
A. (4/10)(2/9) = ?
B. (4/52)(3/51) = ?
C. (30/52)(29)(51) = ?
D. 1 - (0.50)(0.50)(0.50) = ?
Lia D.
asked 11/26/21Letter A: You have 4 blue pens, 3 black, 2 green, and 1 red. You take two without replacing 1 of the pens. Find the probability(blue, then green).
Letter B: Two cards are drawn from a standard deck of 52 cards without a replacement. Find the probability that the cards are aces.
Letter C: Same question as B, but instead of find the probability that the cards are aces, Find the probability that the cards are not going to be any face card (KQJ).
Letter D: If a players free throw rate is 50%, and they make 3 attempts, what is the probability that at least one of the free throws is going to be good?
Inactive Tutor answered 11/26/21
A. (4/10)(2/9) = ?
B. (4/52)(3/51) = ?
C. (30/52)(29)(51) = ?
D. 1 - (0.50)(0.50)(0.50) = ?
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