the length of a rectangle is 2 ft more than twice the width the area is 40 ft2. Find the length and width of the rectangle

Answer 1

L= 2+W

Area = A = LW = (2+W)W = 2W +W^2 = 40

W^2 +2W -40 = 0

use the quadratic formula, ignore the negative square root

W = -1 + or - (1/2)sqr(4+160) = about -1 + or - .6.4 = 5.4 feet wide

L = 7.4 feet long

7.4 x 5.4 = about 40.0 rounded off to one decimal place