Find the equation for a parabola that has a focus at (-2,3) and a directrix y=-3

Question

I have been getting the answer X^2=12y based on the formula X^2=4py. Is this the correct formula I should be using?

Answer 1

First you must get vertex: x = -2; y = (-3 + 3)/2 = 0. So, vertex at point (- 2, 0).

2p = 3 - (- 3) = 6, p = 3.

Equation of parabola: (x + 2)² = 4·3y; (x + 2)² = 12y