Find an equation of the line tangent to the curve at the given point: y=tan(4x^2) ; (√ 𝜋 16 ⁄ , 1)

Answer 1

The equation of the tangent is y = f(x given) + f'(xgiven)(x-xgiven)

f(xgiven) is ygiven

Take the derivative of f(x) and substitute xgiven to find derivative (slope at the point)

I can't go further because the x value given is not clear.