PAP Algebra Question (grade 8)

Question

What is the equation of the line that passes through the point (3,−1) and is perpendicular to the equation y=−3x+2?

Answer 1

(-3,1) is a point on the line

a line perpendicular to y=-3x+2 will have a slope that's the negative inverse of -3, which is 1/3. change the sign from - to + and flip 3/1 upside down.

y= (1/3)x + b where b= y intercept

1 = (1/3)(-3) + b

1= -1 + b

b =2

y = (1/3)x + 2 is the equation of the perpendicular line through the given point

or eliminate the fraction to get 3y=x+6