logarithum help

Question

Assume that log_b 5 ≈ 0.6990, log_b 6 ≈ 0.7782, and log_b 7 ≈ 0.8451.

Use these values and the properties of logarithms to approximate the value.

log_b 36

Answer 1

log5 = .699, log6 = .7782, log7 = .8451 all to the base "b"

loga + logc = logac

log36 =log6 +log6 = 2log6 = 2(.7782) = 1.5564