∫3f(x)+4g(x)dx=3∫f(x)dx+4∫g(x)dx on the interval of 0≤x≤8.
This is simply:
3(33)+4(14)=99+56=155
∫3f(x)+4g(x)dx=3∫f(x)dx+4∫g(x)dx on the interval of 0≤x≤8.
This is simply:
3(33)+4(14)=99+56=155
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