Mark M. answered • 11/13/21
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
∫(from 1 to e^8) (2/x)dx = 2lnx (from 1 to e^8) = 2ln(e8) - 2ln(1) = 2(8) - 2(0) = 16
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