Algebra 1 Math Word Problem

Question

The Kwons invested $6000, part at 7 1/4% and part at 10%, and earned $567 in interest. How much did they invest in each rate?

Answer 1

Mads, the key to these problems is to see you have 2 separate equations given by these words, and then you can solve those equations.

A + B = 6,000 this says that you have $6,000 in two different investments (and we don't know how much is in each investment, we only know the total is $6,000

.0725A + .10B = 567 this says that the interest earned adds up to $567

now you have done the hard part, the easy part is solving the "system of equations " which means changing the situation so we have one variable instead of two variables

A = 6,000 - B

substitute

.0725(6,000 - B) + .10 B = 567

then solve for B, and once you know what B is, it's easy to get A