1.)What is the equation of a line in ax+by=c, passing through (3,-5) and perpendicular to the line passing through (1,-5) and (-5,4)?

Answer 1

slope of the given line = 9/-6= -3/2

slope of the perpendicular line = 2/3

through the point (3,-5)

-5 = (2/3)(3) + b

b = -5 -2 = -7

y = 2x/3 -7 in y=mx+b slope intercept form

3y =2x -21

2x-3y = 21 in standard ax+by = c form, where a=2, b=-3 and c=21