Write the Equation of the line that has a slope of 3/4 and passes through the point (-6,8)

Answer 1

y-y₀ = m(x-x₀)

For m = 3/4 and (x₀, y₀) = (-6,8)

y-8 = (3/4)(x- -6)

y = 3x/4+18/4 +8

y = 3x/4 + 25/2

Answer 2

You can use the point slope equation to solve this. Based on what you are given, you have the following values:

m=3/4

x1=-6

y1=8

(y-y1)=m(x-x1) Plugging in values

y-8=3/4(x-(-6)) Simplify

y-8=3/4(x+6) Distribute

y-8=3/4x+18/4 Add 8 to both sides

y=3/4x+25/2