Use a weighted average: Let H1 = Amount of 30% solution and H2 = Amount of 55% solution
H1 + H2 = 437.5 liters
{ (.3)H1 + (.55)H2 }/( H1 + H2) = .45
Solving using the 2 equations, we find that H1 = 175 Liters and H2 = 262.5 Liters

Mark J.
11/07/21
Dante B.
asked 11/06/21Theresa Morgan, a chemist, has a 30% hydrochloric acid solution and a 55% hydrochloric acid solution. How many liters of each should she mix to get 437.5 liters of a hydrochloric acid solution with a 45% acid concentration?
Use a weighted average: Let H1 = Amount of 30% solution and H2 = Amount of 55% solution
H1 + H2 = 437.5 liters
{ (.3)H1 + (.55)H2 }/( H1 + H2) = .45
Solving using the 2 equations, we find that H1 = 175 Liters and H2 = 262.5 Liters
Mark J.
11/07/21
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Dante B.
thank you!!11/07/21