Specific Heat Capacity Show work Please!

Question

A heat energy of 645 J is applied to a sample of glass with a mass of 28.4 g. Its temperatureincreases from –11.6 ∞C to 15.5 ∞C. Calculate the specific heat of glass.

[0.84 J/g C] <=== Answer

Answer 1

Hello Christopher,

For this problem, you want to use the specific heat formula (Q=m Cs delta T, where Q is heat, m is mass, Cs is the specific heat constant for the given substance, and delta T is the change in temperature).

Our heat is 645 J(Q), mass is 28.4 g, and our change in temperature is 15.5 -(-11.6)(remember delta is final minus initial). So when we plug these in:

645 J = (28.4g) Cs (15.5^OC-(-11.6^OC))

We can simplify it to

645 J = (28.4g) Cs (27.1^OC)

Now we solve for Cs,

Cs= 0.838 J/g*^OC

I hope that this helps!