The length of a rectangle is twice its width. If the perimeter of the rectangle is 54 in, find its length and width.

Answer 1

Let L = Length of the rectangle and W = Width of the rectangle

The perimeter is 2L + 2W

It is given that L = 2W

So, Perimeter = 4W + 2W = 54

Or 6W = 54

Then W = 9 (Width)

L = 2W = 2(9) = 18 (Length)