solve parameters a, h and v for y=x²-6x+20

Answer 1

Do you mean a, h, k

y = a (x-h)² + k = ax² - 2axh + ah² + k = x² - 6x + 20

Comparing coefficients :

x² : a = 1

x : -2ah = -6. a = 1 so h = 3

Constant : ah² + k = 20. a = 1, h = 3 giving k = 11

So y = (x-3)² + 11, with a=1, h = 3, k = 11.

So the vertex would be at (h,k) = (3,11)