Find f('(16) if f(x)=(7x^2+6x+3)/(√x)

Answer 1

f(x) = (7x^2 +6x +3)/sqrx

f'(x) = (7x^2+6x+3)(-1/x) + 1/sqrx)(14x +6x)

f'(16)= (7(16)^2 +6(16) +3)(-1/16) + 1/4)(14(16) +6(16)

= -112 -6 -3/16 + 56 + 96

= -118 + 152 - 3/16

= 34 - 3/16

= 33 13/16