n = (z alpha/2 * S/E)^2
where n = sample size, z alpha/2 = critical value for 99% confidence = 2.58, S = 1 and E = 0.011.
n = (2.58 * 1 / 0.011)^2 = 55011.57 ~ 55012
Sample size does not seem practical.
Rin A.
asked 10/29/21Assume that all grade-point averages are to be standardized on a scale between 0 and 4. How many grade-point averages must be obtained so that the sample mean is within 0.011 of the population mean? Assume that 99% confidence level is desired. If using the range rule of thumb, σ can be estimated as
range/4=4-0/4=1 Does the sample size seem practical?
n = (z alpha/2 * S/E)^2
where n = sample size, z alpha/2 = critical value for 99% confidence = 2.58, S = 1 and E = 0.011.
n = (2.58 * 1 / 0.011)^2 = 55011.57 ~ 55012
Sample size does not seem practical.
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