Raymond B. answered 10/26/21
Math, microeconomics or criminal justice
{a,b,c}, {a,b}, {a,c},{b,c}, {a}, {b}, {c} and the null set with no elements
that's 8 subsets
or calculate them with combinations
3C3 = 3!/3!0!= 1
3C2 = 3!/2!1! = 3
3C1 = 3!/1!2! = 3
3C0 = 3!/0!3! = 1
1+3+3+1 = 8
2^3 = 8
or add up the 4th row of Pascal's triang2le
1
11
121
1331