What is the rate of the rowing team in calm water and the rate of the current.

Question

A rowing team rowing with the current traveled 48 km in 4 h. Rowing against the current, the team rowed 16 km in the same amount of time. Find the rate of the rowing team in calm water and the rate of the current.

Answer 1

Let = speed of boat in still water and let y = speed of current

Speed with the current = x + y

Speed against the current = x - y

Distance = (Rate)(Time)

So we get the following system of equations:

4(x + y) = 48

4(x - y) = 16

Solve for x and y.

Answer 2

Solutions to similar problems have been presented previously. Use them as a model, attempt a solution, then ask for assistance.