What is an equation of the line that passes through the point (1,6) and is perpendicular to the line x+3y=27?

Answer 1

The given equation can be put in the form y = -(1/3)x + 9.

We see that the slope of the given line is -1/3.

Since the slope of the perpendicular line is the negative reciprocal of the given line, our slope is 3.

Using the point-slope form, an equation of the desired line is y - 6 = 3(x - 1)

So, y = 3x + 3