OK, I think the expression is:
(2x4y)3
There are three terms in the expression: 2, x4, and y. You need to cube them all:
= 23·(x4)3·y3
When you raise a power to a power, as in (x4)3, you multiply the exponents:
= 8x12y3
Christian B.
asked 10/22/21OK, I think the expression is:
(2x4y)3
There are three terms in the expression: 2, x4, and y. You need to cube them all:
= 23·(x4)3·y3
When you raise a power to a power, as in (x4)3, you multiply the exponents:
= 8x12y3
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