f f(1)=6f(1)=6 and f(n)=f(n-1)-5f(n)=f(n−1)−5 then find the value of f(5)f(5)

Answer 1

We start with f(1) = 6

Using f(n) = f(n - 1) - 5, we can find f(2). Since n = 2:

f(2) = f(2 - 1) - 5 = f(1) - 5 = 6 - 5 = 1

Now we can find f(3) using f(n) = f(n - 1) - 5, since n = 3::

f(3) = f(3 - 1) - 5 = f(2) - 5 = 1 - 5 = -4

Now we can find f(4) using f(n) = f(n - 1) - 5, since n = 4:

f(4) = f(4 - 1) - 5 = f(3) - 5 = -4 - 5 = -9

Now we can find f(5) using f(n) = f(n - 1) - 5, since n = 5:

f(5) = f(5 - 1) - 5 = f(4) - 5 = -9 - 5 = -14