Consecutive integers

Question

4 consecutive integers with the sum of 106

Answer 1

Consecutive integers

4 consecutive integers with the sum of 106

Hello Scarlet,

x + (x+1) + (x+2) + (x+3) = 106

4x + 6 = 106

4x = 100

x = 25

Numbers are, 25, 26, 27, 28

Answer 2

x + (x + 1) + (x + 2) + (x + 3) = 106; 4x = 100; x = 25.

Answer: 25, 26, 27, 28