Math word problem

Question

A waitress sold 19 ribeye steak dinners and 18 grilled salmon​ dinners, totaling ​$566.87 on a particular day. Another day she sold 30 ribeye steak dinners and 6 grilled salmon​ dinners, totaling ​$580.05. How much did each type of dinner​ cost?

Answer 1

19r + 18g = 566.87

30r + 6g = 580.05

90r +18g = 1740.15

19r + 18g = 566.87

subtract

71r = 1173.28

r = 1173.28/71 = $16.53 for a ribeye steak

g = 580.05 -30(16.53))/6 = 580.05-495.90)/6= 85.15/6= $14.19 for a grilled salmon dinner