Mark M. answered 10/13/21
Retired math prof. Very extensive Precalculus tutoring experience.
If f(x) is a polynomial function with integer coefficients and if 3, -1, 3i, and -√3 are roots, then -3i and √3 must also be roots.
A possible function is f(x) = (x-3)(x+1)(x-3i)(x+3i)(x-√3)(x+√3) = (x2-2x-3)(x2+9)(x2-3)
Kaela W.
so would the second one be (x+1)(x-2)(x+5)(x-5+√6/4)10/13/21