Two bike riders x and y both start at 2pm riding towards each other from 40 km apart. X rides at 30km/h, Y at 20 km/h. If they meet after t hours find when and where they meet.

Answer 1

40 km apart, they start at 2pm and meet at 2:48 pm

x rides at 30 kmh

y rides at 20 kmh

riding at each other

distance = speed times time

d= st

t = d/s = (z/30) = (40-z)/20

x traveled for z km = 24 km

y traveled 40-z km = 16 km

24/30 =16/20 = 4/5 hr = (4/5)60 = 48 minutes

they meet in 48 minutes

z/30 = (40-z)/20

cross multiply

20z = 1200-30z

50z = 1200

z = 1200/50 = 24 km

40-24 = 16 km

in 48 minutes, x rides 24 km and y rides 16 km

starting at 2 pm, meeting at 2:48 pm

distance = speed times time. km = km per hour times hours

d=st, 24= 30(4/5) for x

d=st 16 =20(4/5) for y