hSuppose you flip a coin and keep a record of the results. In how many ways could you obtain at least one head if you flip the coin five times?

Question

how would i solve this ?

Answer 1

nCr = n!/(n-r)!r!

for 5 flips, n=5

for just zero heads in 5 flips r =0

5C0 = 5!/(5-0)!0! = 5!/5!0! = 1

2^5 = 32 = total ways of results for 5 flips of heads or tails

ways to get at least one head = 32-1 = 31