find two consecutive integers such that ten more than twice the smaller is seven less than three times the larger

Answer 1

Hello, Isabella,

Let's say X is the first integer. Then (X+1) will be the second.

"ten more than twice the smaller"

can be written as 2(X)+10 [this is 10 more than twice the smaller]

"seven less than three times the larger"

can be written as 3(X+1)-7

"is"

says these two quantities are equal.

2(X)+10 = 3(X+1)-7

2X+10 = 3X - 4

-X = -16

X = 14 X+1 = 15 The two consesecutive integers are 14 and 15.

[2*14+10= 3*15-7]?

38 = 45-7? 38=38 YES