Write an equation in slope-intercept form for a line that passes through the points (-2,-16) & (1,5)

Answer 1

point (-2,-16) (1,5)

slope intercept form y=mx+b

m=y^2-y^1/x^2-x^1 y=7x+b

m=5-(-16)/1-(-2) Using the points (1,5) Correct Answer y=7x-2

m=5+16/1+2 5=7(1)+b

m=21/3 5=7+b

m=7 b=5-7 b=-2

Answer 2

The slope of the line is given by: -16 -5 / -2 -1 = -21 / -3 = +7.

The slope intercept form of a straight line is Y = mX + b or Y = 7X + b.

substitute either given point in the last equation and calculate b.

5 = 7 x 1 + b or b = -2

or -16 = 7 x -2 +b or b = -2. The equation is Y = 7X -2

Answer 3

First,use the slope formula to find the slope. The slope formula is (y₂ - y₁) / (x₂ -x₁) .Plug in the values from the coordinate points to calculate the slope.

y_{2 = 5} y_{1 = -16}

x_{2 = 1} x_{1 = -2}

Once you find the slope, plug it in to the equation, y=mx+b, in the "m" position.

After that, take ONE of your coordinate points and plug the x coordinate and the y coordinate into the y=mx+b format (where the x and y variables are) and then solve for b. Once you solve for b, you can write the equation. Use the slope you found to plug in for m and the value you found for b to write the final equation.