In circle O, MN = PQ, OU bisects MN at T and OV bisects PQ at S. If MN is one less than twice PQ, find PS.

Answer 1

OK, without seeing the figure, let's see if I read this problem correctly. From the problem statement we have:

MN = PQ

MN = 2PQ - 1

Since MN = PQ, we can substitute PQ in place of MN in the second equation:

PQ = 2PQ - 1

1 = PQ

Since OV bisects PQ at point S, we have

PS = (1/2)PQ

PS = (1/2)(1)

PS = 1/2

Not sure what points O, U, and T are for.