Algebra One Problem

Question

Bella has a stack of 41 bills (ones, fives, and tens) in an envelope. She has 3 less tens than fives and the quantity of ones doubles the number of fives. Write and solve an equation to determine how many of each bill type she has.

Answer 1

T=F-3

W=2F

W+F+T =41

2F+F+F-3 = 41

4F =44

F =11 Fives

T= 8 Tens

W = 22 Ones

Answer 2

Hi Cozlo, I hope the explanation below helps.

X - quantity of one-dollar bills

Y - quantity of five-dollar bills

Z - quantity of ten-dollar bills

The equations are:

1. total number of bile = 41
2. ten-dollar bills in terms of five-dollar bills
3. one-dollar bills in terms of five-dollar bill

x + y + z = 41

z = y - 3

x = 2y

x = 22, y = 11, z = 8