Algebra One Problem

Question

Bella has a stack of 41 bills (ones, fives, and tens) in an envelope. She has 3 less tens than fives and the quantity of ones doubles the number of fives. Write and solve an equation to determine how many of each bill type she has.

Answer 1

T + F + W = 41

T= number of 10's, F=number of 5's, W=number of Ones

T = F -3

W =2F

F-3 + F + 2F = 41

4F = 44

F = 11 fives

T = 8 tens

W = 22 ones

Answer 2

Let

x= number of one dollar bills

y= number of five dollars bills

z= number of ten dollars bills

x + y + z = 41

y -3= z

2y = x

------

substitute:

2y + y + y - 3 = 41

4y - 3 = 41

4y = 44

y= 11

x = 2(11) = 22

z = 11-3 = 8