A rocket is launched from atop a cliff. Its height h (in ft) at time t (in sec) is h=-16t^2+110t+69. How long will it take for the rocket to hit the ground after it is launched

Answer 1

h = -16t^2 + 110t + 69 = 0

t= 110/32 + (1/32)sqr(110^2 +64(69))

= about 7.454 seconds to reach the ground