
Yefim S. answered 10/05/21
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∑1∞e1/n/n.
Let using limit comparison test with divergent harmonic series: lim n →∞ (e1/n/n)/(1/n) = lim n → ∞ e1/n = e0 = 1. So, by comparison test given series also diverges
Jessie T.
I thought it was convergent, Thanks a lot!10/05/21