Eric M. answered 03/10/15
Tutor
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(11)
Chemistry, Mathematics, Physical Sciences, Writing...take your pick!
Hello May,
I'd normally say that, without the graph, you're out of luck. But a valuable clue is that the graph goes through (0, 2).
The answer, then, is A but ONLY if you parse A as "f(x) = (1/3)x + 1." Then at x = 0, you have f(0) = (1/3)0 + 1 = 2, and the graph goes through (0, 2).
I originally parsed this as "f(x) = (1/3)x+1, and B similarly, in which case none of the answers works.
Given the description, however, none of the answers fits anyway, as the graph of A "begins" in the second quadrant at very high values of y, nowhere near y = 1. For example, at x = -6, f(x) = 36 + 1 = 730. It passes through (0, 2) while leveling off the whole time, asymptotically approaching y = 1 as x approaches infinity.
Gee whiz...be careful!
Eric M.
McMinnville OR