N=3; -3 and 3+5i are zeros; f(2) =130

Answer 1

x= 3+5i

x-3 = 5i

(x-3)^2 =-25

x^2 -6x + 34 = 0'

x^2-6x +34 is one factor

(x^2 - 3) = x^2 -6x +9 is another factor

multiply the factors together

f(x) = a(x^2-6x+34)(x^2-6x +9)

f(2)=130= 26a

a=5

f(x)= 5(x^4-12x^3 +31x^2+246x +306)

= 5x^4 -60x^3 + 155x^2+ 1230x + 1530