Solving a Distance

Question

Two cyclists leave towns 156 miles apart at the same time and travel toward each other. One cyclist travels 7 (mi)/h faster than the other. If they meet in 4 hours, what is the rate of each cyclist?

Answer 1

(7+r)(4)+ 4r = 156

8r = 156-28 = 128

r = 128/8 = 16 mph for the slower cyclist

7+r = 23 mph for the faster cyclist

4(16+23) = 4(39) = 156