The length of a rectangle is 4 yd longer than it’s width. If the perimeter of the rectangle is 44 yd, find it’s area

Question

The length of a rectangle is 4 yd longer than it’s width. If the perimeter of the rectangle is 44 yd, find it’s area

Answer 1

L=4+W

2(L+W) = 44

L+W = 44/2 = 22

L=22-W = 4+W

2W =22-4 = 18

W = 18/2 = 9 yards wide

L = 13 yards long

2(9+13) = 2(22) = 44 yard perimeter